Square Root.
The number \(s\) is called a square root of a number \(b\) if \(s^2=b\text{.}\)
Section 5.2 Square Roots and Cube Roots
Subsection What is a Square Root?
Suppose we would like to draw a square whose area is 25 square inches. How long should each side of the square be?
Because the formula for the area of a square is \(A=s^2\text{,}\) the side \(s\) should satisfy the equation \(s^2=25\text{.}\) We want a number whose square is 25. As you can probably guess, the length of the square should be 5 inches, because \(5^2=25\text{.}\) We say that 5 is a square root of 25.
Finding a square root of a number is the opposite of squaring a number.
Example 5.13.
Find a square root of 25, and a square root of 144.
Solution.
5 is a square root of 25 because \(5^2=25\text{.}\)
12 is a square root of 144 because \(12^2=144\text{.}\)
Look Closer.
5 is not the only square root of 25, because \((-5)^2=25\) as well. Thus, 25 has two square roots, \(5\) and \(-5\text{.}\)
Every positive number has two square roots, one positive and one negative.
Reading Questions Reading Questions
1.
What is the square root of a number \(n\text{?}\)
Answer.
A number whose square is \(n\)
Subsection Radicals
The positive square root of a number is called the principal square root. The symbol \(\sqrt{\hphantom{00}}\) denotes the positive or principal square root. Thus, we may write
\begin{equation*}
\sqrt{25} = 5~~~~~~\text{and}~~~~~~\sqrt{144}=12
\end{equation*}
The symbol \(\sqrt{\hphantom{00}}\) is called a radical sign, and the number inside is called the radicand. Square roots are often called radicals.
What about the other square root, the negative one? If we want to indicate the negative square root of a number, we place a negative sign outside the radical sign, like this:
\begin{equation*}
-\sqrt{16}=-4~~~~~~\text{and}~~~~~~ {-\sqrt{49}}=-7
\end{equation*}
If we want to refer to both square roots, we use the symbol \(\pm\text{,}\) read "plus or minus." For example,
\begin{equation*}
\pm \sqrt{36}=\pm 6,~~~~\text{which means}~~~~6~~\text{or}~~ {-6}
\end{equation*}
Note that zero has only one square root: \(\sqrt{0}=0\text{.}\)
Example 5.14.
Find each square root.
- \(\displaystyle -\sqrt{81} = -9\)
- \(\displaystyle \pm \sqrt{\dfrac{64}{121}} = \pm \dfrac{8}{11}\)
Reading Questions Reading Questions
2.
What is the positive square root of a number called?
Answer.
The principal square root
3.
What is a radicand?
Answer.
The number inside a radical sign
Every positive number has two square roots, and zero has exactly one square root. What about the square root of a negative number? For example, can we find \(\sqrt{-4}\text{?}\)
The answer is No, because the square of any number is positive (or zero). Try this yourself: The only reasonable candidates for \(\sqrt{-4}\) are \(2\) and \(-2\text{,}\) but
\begin{align*}
2^2 \amp = \underline{\hphantom{000000}}\\
(-2)^2 \amp = \underline{\hphantom{000000}}
\end{align*}
We cannot find the square root of a negative number. We say that the square root of a negative number is undefined.
Reading Questions Reading Questions
4.
How do we find the square root of a negative number?
Answer.
The square root of a negative number is undefined.
Subsection Rational and Irrational Numbers
Rational Number.
A rational number is one that can be expressed as a quotient (or ratio) of two integers, where the denominator is not zero.
The term "rational" has nothing to do with being reasonable or logical; it comes from the word ratio. Thus, any fraction such as
\begin{equation*}
\dfrac{2}{3},~~~ \dfrac{-4}{7},~~~ \text{or}~~~ \dfrac{15}{8}
\end{equation*}
is a rational number. Integers are also rational numbers, because any integer can be written as a fraction with a denominator of 1. (For example, \(6= \dfrac{6}{1}\)). All of the numbers we have encountered before this chapter are rational numbers.
Reading Questions Reading Questions
5.
What is a rational number?
Answer.
One that can be expressed as a quotient of two integers
Every fraction can be written in decimal form.
Decimal Form of a Rational Number.
The decimal representation of a rational number has one of two forms.
- The decimal representation terminates, or ends.
- The decimal representation repeats a pattern.
Example 5.15.
Write the decimal form for each rational number.
- \(\displaystyle \dfrac{3}{4}\)
- \(\displaystyle \dfrac{4}{11}\)
Solution.
- We can use a calculator or long division to divide the numerator by the denominatorto find \(\dfrac{3}{4}=0.75\text{.}\)
- We divide 4 by 11 to find \(\dfrac{4}{11}=0.363636 \ldots = 0.\overline{36}\text{.}\) The line over the digits 36 is called a repeater bar, and it indicates that those digits are repeated forever.
Reading Questions Reading Questions
6.
How can you recognize a rational number in its decimal form?
Answer.
It either terminates or repeats a pattern.
What about the decimal form for \(\sqrt{5}\text{?}\) If you use a calculator with an eight-digit display, you will find
\begin{equation*}
\sqrt{5} \approx 2.236~ 068
\end{equation*}
However, this number is only an approximation, and not the exact value of \(\sqrt{5}\text{.}\) (Try squaring \(2.236~ 068\) and you will see that
\begin{equation*}
2.236~ 068^2 = 5.000~ 000~ 100~ 624
\end{equation*}
which is not exactly 5, although it is close.) In fact, no matter how many digits your calculator or computer can display, you can never find an exact decimal equivalent for \(\sqrt{5}\text{.}\) \(\sqrt{5}\) is an example of an irrational number.
Irrational Number.
An irrational number is one that cannot be expressed as a quotient of two integers.
Look Closer.
There is no terminating decimal fraction that gives the exact value of \(\sqrt{5}\text{.}\) The decimal representation of an irrational number never ends, and does not repeat any pattern! The best we can do is round off the decimal form and give an approximate value. Nonetheless, an irrational number still has a precise location on the number line, just as a rational number does. The figure below shows the locations of several rational and irrational numbers on a number line. 
Real Numbers.
Each point on a number line corresponds either to a rational number or an irrational number, and these numbers fill up the number line completely. The rational and irrational numbers together make up the real numbers, and the number line is sometimes called the real line.
Reading Questions Reading Questions
7.
What are the rational and irrational numbers together called?
Answer.
The real numbers
It is important that you understand the distinction between an exact value and an approximation.
Example 5.16.
- We cannot write down an exact decimal equivalent for an irrational number.\begin{align*} \sqrt{5}~~~~ \amp \text{indicates the exact value of the square root of 5}\\ 2.236068~~~~ \amp \text{ is an approximation to the square root of 5} \end{align*}
- We often use a decimal approximation for a rational number.\begin{align*} \dfrac{2}{3}~~~~ \amp \text{indicates the exact value of 2 divided by 3}\\ 0.666667~~~~ \amp \text{is an approximation for}~\dfrac{2}{3} \end{align*}
Of course, even though many radicals are irrational numbers, some radicals, such as \(\sqrt{16}=4\) and \(\sqrt{\dfrac{9}{25}}\text{,}\) represent integers or fractions. Integers such as 9 and 25, whose square roots are whole numbers, are called perfect squares.
Subsection Order of Operations
When we evaluate algebraic expressions that involve radicals, we must follow the order of operations as usual. Square roots occupy the same position as exponents in the order of operations: They are computed after parentheses but before multiplication.
Example 5.17.
Find a decimal approximation to three decimal places for \(8-2\sqrt{7}\text{.}\)
Solution.
You may be able to enter this expression into your calculator just as it is written. If not, you must enter the operations in the proper order. The expression has two terms, 8 and \(-2\sqrt{7}\text{,}\) and the second term is the product of \(\sqrt{7}\) with \(-2\text{.}\)
We should not begin by subtracting 2 from 8, because multiplication precedes subtraction. First, we find an approximation for \(\sqrt{7}\text{:}\)
\begin{equation*}
\sqrt{7} \approx 2.6457513
\end{equation*}
Do not round off your approximations at any intermediate step in the problem or you will lose accuracy at each step! You should be able to work directly with the value on your calculator’s display.
Next, we multiply our approximation by \(-2\) to find
\begin{equation*}
-2\sqrt{7} \approx -5.2905026
\end{equation*}
Finally,we add 8 to get
\begin{equation*}
8-2\sqrt{7} \approx 2.7084974
\end{equation*}
Rounding to three decimal places gives 2.708
Caution 5.18.
In Example 5.17, it is not true that \(8-2\sqrt{7}\) is equal to \(6\sqrt{7}\text{.}\) The order of operations tells us that we must perform the multiplication \(-2\sqrt{7}\) first, then add the result to \(8\text{.}\) You can verify that \(6\sqrt{7} \approx 15.874\text{,}\) which is not the same answer we got in Example 5.17.
We can now update the order of operations by modifying Steps 1 and 2 to include radicals.
Order of Operations.
- Perform any operations inside parentheses, or above or below a fraction bar.
- Compute all indicated powers and roots.
- Perform all multiplications and divisions in the order in which they occur from left to right.
- Perform additions and subtractions in order from left to right.
Reading Questions Reading Questions
8.
When do we evaluate roots in the order of operations?
Answer.
After parentheses but before products and quotients
Subsection Cube Roots
Imagine a cube whose volume is 64 cubic inches. What is the length, \(c\text{,}\) of one side of this cube? Because the volume of a cube is given by the formula \(V=c^3\text{,}\) we must find a number that satisfies
\begin{equation*}
c^3=64
\end{equation*}
We are looking for a number \(c\) whose cube is 64. With a little trial and error we can soon discover that \(c=4\text{.}\) The number \(c\) is called the cube root of 64, and is denoted by \(\sqrt[3]{64}\text{.}\)
Cube Root.
The number \(c\) is called a cube root of a number \(b\) if \(c^3=b\text{.}\)
Example 5.19.
- \(\sqrt[3]{-64}=-4\) because \((-4)^3=-64\text{.}\)
- \(\sqrt[3]{9}\) is an irrational number approximately equal to \(2.08\text{,}\) because \(2.08^3=8.998912\text{.}\)
Recall that every positive number has two square roots, and that negative numbers do not have square roots. The situation is different with cube roots.
Every number has exactly one cube root. The cube root of a positive number is positive, and the cube root of a negative number is negative.
Just as with square roots, some cube roots are irrational numbers and some are not. Cube roots are treated the same as square roots in the order of operations.
Reading Questions Reading Questions
9.
What is the cube root of a number \(n\text{?}\)
Answer.
A number whose cube is \(n\)
10.
How many cube roots does a negative number have?
Answer.
One
Subsection Skills Warm-Up
Exercises Exercises
Exercise Group.
Solve the equation for \(x\text{.}\)
1.
\(3x+5=17\)2.
\(3x+k=17\)3.
\(\dfrac{x}{4}-9=-4\)4.
\(\dfrac{x}{4}-m=-4\)5.
\(2x-3=4x+7\)6.
\(2x-c=4x+7)\)7.
\(6x+1=3(2-x)\)8.
\(bx+1=3(2-x)\)Subsubsection Answers to Skills Warm-Up
- \(\displaystyle 4\)
- \(\displaystyle \dfrac{17-k}{3}\)
- \(\displaystyle 20\)
- \(\displaystyle 4(-4+m)\)
- \(\displaystyle -5\)
- \(\displaystyle \dfrac{-c-7}{2}\)
- \(\displaystyle \dfrac{5}{9}\)
- \(\displaystyle \dfrac{5}{b+3}\)
Subsection Lesson
Subsubsection Activity 1: Roots and Radicals
Exercises Exercises
1.
Find two square roots for each number.
- \(\displaystyle 225\)
- \(\displaystyle \dfrac{4}{9}\)
2.
Simplify each radical, if possible.
- \(\displaystyle \sqrt{64}\)
- \(\displaystyle \sqrt{-64}\)
- \(\displaystyle -\sqrt{64}\)
- \(\displaystyle \pm \sqrt{-64}\)
3.
Evaluate each cube root. (Use a calculator if necessary.)
- \(\displaystyle \sqrt[3]{8}\)
- \(\displaystyle \sqrt[3]{-125}\)
- \(\displaystyle \sqrt[3]{-1}\)
- \(\displaystyle \sqrt[3]{50}\)
4.
- If \(~p=\sqrt{d}~\text{,}\) then \(~d= \fillinmath{XXXXXXXXXX}\)
- If \(~v^2=k~\text{,}\) then \(~v= \fillinmath{XXXXXXXXXX}\)
5.
- Explain why the square root of a negative number is undefined.
- If \(x \gt 0\text{,}\) explain the difference between \(\sqrt{-x}\) and \(-\sqrt{x}\text{.}\)
- Explain why you can always simplify \(\sqrt{x}~\sqrt{x}\text{,}\) as long as \(x\) is non-negative.
- Explain why you can always simplify \(\dfrac{x}{\sqrt{x}}\text{,}\) as long as \(x\) is positive.
6.
- Make a list of the squares of all the integers from 1 to 20. These are the first 20 perfect squares. Now make a list of square roots for these perfect squares.
- Make a list of the cubes of all the integers from 1 to 10. These are the first 10 perfect cubes. Now make a list of cube roots for these perfect cubes.
Subsubsection Activity 2: Rational Numbers
Exercises Exercises
1.
Find the decimal form for each rational number. Does it terminate?
- \(\displaystyle \dfrac{2}{3}\)
- \(\displaystyle \dfrac{5}{2}\)
- \(\displaystyle \dfrac{13}{27}\)
- \(\displaystyle \dfrac{962}{2000}\)
2.
Give a decimal equivalent for each radical, and identify it as rational or irrational. If necessary, round your answers to three decimal places.
| \(\sqrt{1}= \fillinmath{XXXXXXXXXXXXXXX}\) | \(\hphantom{0000}\) | \(\sqrt{6}= \fillinmath{XXXXXXXXXXXXXXX}\) |
| \(\sqrt{2}= \fillinmath{XXXXXXXXXXXXXXX}\) | \(\hphantom{0000}\) | \(\sqrt{7}= \fillinmath{XXXXXXXXXXXXXXX}\) |
| \(\sqrt{3}= \fillinmath{XXXXXXXXXXXXXXX}\) | \(\hphantom{0000}\) | \(\sqrt{8}= \fillinmath{XXXXXXXXXXXXXXX}\) |
| \(\sqrt{4}= \fillinmath{XXXXXXXXXXXXXXX}\) | \(\hphantom{0000}\) | \(\sqrt{9}= \fillinmath{XXXXXXXXXXXXXXX}\) |
| \(\sqrt{5}= \fillinmath{XXXXXXXXXXXXXXX}\) | \(\hphantom{0000}\) | \(\sqrt{10}= \fillinmath{XXXXXXXXXXXXXXX}\) |
3.
True or False.
- If a number is irrational, it cannot be an integer.
- Every real number is either rational or irrational.
- Irrational numbers do not have an exact location on the number line.
- We cannot find an exact decimal equivalent for an irrational number.
- 2.8 is only an approximation for \(\sqrt{8}\text{;}\) the exact value is 2.828427125.
- \(\sqrt{17}\) appears somewhere between 16 and 18 on the number line.
Subsubsection Activity 3: Order of Operations
Exercises Exercises
1.
A radical symbol acts like parentheses to group operations. Any operations that appear under a radical should be performed before evaluating the root.
- Simplify \(~~\sqrt{6^2-4(3)}\)
- Approximate your answer to part (a) to three decimal places.
- Explain why the following is incorrect:\begin{align*} \sqrt{6^2-4(3)} \amp = \sqrt{6^2}-\sqrt{4(3)}\\ \amp = \sqrt{36} - \sqrt{12}\\ \amp \approx 6-3.464 = 2.536 \end{align*}
2.
- Simplify \(~~5-3\sqrt{16+2(-3)}\)
- Approximate your answer to part (a) to three decimal places.
3.
Evaluate \(~~2x^2-\sqrt{9-x}~~\) for \(x=-3\text{.}\)
Subsubsection Wrap-Up
Objectives.
In this Lesson we practiced the following skills:
- Computing square roots and cube roots
- Using radical notation
- Distinguishing between rational and irrational numbers
- Distinguishing between exact values and approximations
- Simplifying expressions involving radicals
Questions.
- Explain why you don’t need a calculator to evaluate \(~\dfrac{23}{\sqrt{23}}\text{.}\)
- Explain why you cannot write down an exact decimal form for \(\sqrt{6}\text{.}\)
- Explain why \(~\sqrt{3^2+4^2} \not= 3+4\text{.}\)
Subsection Homework Preview
Exercises Exercises
1.
Simplify.
- \(\displaystyle 8-3\sqrt{25}\)
- \(\displaystyle (3\sqrt{16})(-2\sqrt{81})\)
- \(\displaystyle \dfrac{3-\sqrt{36}}{6}\)
2.
Find a decimal approximation rounded to two places.
- \(\displaystyle -3+\sqrt{34}\)
- \(\displaystyle \sqrt{6^2-4(3)}\)
- \(\displaystyle \sqrt[3]{\dfrac{18}{5}}\)
3.
Simplify.
- \(\displaystyle 2\sqrt{x}(8\sqrt{x})\)
- \(\displaystyle \dfrac{6m}{3\sqrt{m}}\)
- \(\displaystyle \sqrt[3]{H}(\sqrt[3]{H})(\sqrt[3]{H})\)
4.
Evaluate for \(x=3,~y=5\text{.}\) Round to hundredths.
- \(\displaystyle \sqrt{x^2+y^2}\)
- \(\displaystyle (x+y)^2-(x^2+y^2)\)
- \(\displaystyle \sqrt{x}+\sqrt{y}-\sqrt(x+y)\)
Subsubsection Answers to Homework Preview
- \(\displaystyle -7\)
- \(\displaystyle -216\)
- \(\displaystyle -\dfrac{1}{2}\)
- \(\displaystyle 2.83\)
- \(\displaystyle 4.90\)
- \(\displaystyle 1.53\)
- \(\displaystyle 16x\)
- \(\displaystyle 2\sqrt{m}\)
- \(\displaystyle H\)
- \(\displaystyle 5.83\)
- \(\displaystyle 30\)
- \(\displaystyle 1.14\)
Exercises Homework 5.2
Exercise Group.
For Problems 1–3, simplify. Do not use a calculator!
1.
- \(\displaystyle 4-2\sqrt{64}\)
- \(\displaystyle \dfrac{4-\sqrt{64}}{2}\)
Answer.
- \(\displaystyle -12\)
- \(\displaystyle -2\)
2.
- \(\displaystyle \sqrt{9-4(-18)}\)
- \(\displaystyle \sqrt{\dfrac{4(50)-56}{16}}\)
3.
- \(\displaystyle 5\sqrt[3]{8}-\dfrac{\sqrt[3]{64}}{8}\)
- \(\displaystyle \dfrac{3+\sqrt[3]{-729}}{6-\sqrt[3]{-27}}\)
Answer.
- \(\displaystyle \dfrac{19}{2}\)
- \(\displaystyle \dfrac{-2}{3}\)
Exercise Group.
For Problems 4–9, give a decimal approximation rounded to thousandths.
4.
\(5\sqrt{3}\)5.
\(\dfrac{-2}{3}\sqrt{21}\)Answer.
\(-3.055\)
6.
\(-3+2\sqrt{6}\)7.
\(2+6\sqrt[3]{-25}\)Answer.
\(-15.544\)
8.
\(\dfrac{8-2\sqrt{2}}{4}\)9.
\(3\sqrt{3}-3\sqrt{5}\)Answer.
\(-1.512\)
Exercise Group.
For Problems 10–12, choose the best approximation. Do not use a calculator!
10.
\(\sqrt{72}\)
- 7
- 8
- 36
- 64
11.
\(\sqrt{13}\)
- 6
- 6.5
- 3.5
- 4
Answer.
c
12.
\(\sqrt{134}\)
- 11
- 11.5
- 12
- 15
13.
Each number below is approximately the square root of a whole number. Find the whole number.
- 9.220
- 12.961
- 63.891
Answer.
- 85
- 168
- 4082
14.
- Evaluate \(~\sqrt{x^2}~\) for \(~x=3, 5, 8,\) and \(12\text{.}\)
- Simplify \(~\sqrt{a^2}~\) if \(a \ge 0\text{.}\)
Exercise Group.
For Problems 15–18, use the definitions of square root and cube root to simplify each expression. Do not use a calculator!
15.
- \(\displaystyle (\sqrt{16})(\sqrt{16})\)
- \(\displaystyle \sqrt{29}(\sqrt{29})\)
- \(\displaystyle \sqrt{x}(\sqrt{x})\)
Answer.
- \(\displaystyle 16\)
- \(\displaystyle 29\)
- \(\displaystyle x\)
16.
- \(\displaystyle (\sqrt{7})^2\)
- \(\displaystyle (\sqrt[3]{20})^3\)
- \(\displaystyle (\sqrt[3]{4})(\sqrt[3]{4})(\sqrt[3]{4})\)
17.
- \(\displaystyle \dfrac{6}{\sqrt{6}}\)
- \(\displaystyle \dfrac{-15}{\sqrt{15}}\)
- \(\displaystyle \dfrac{2m}{\sqrt{m}}\)
Answer.
- \(\displaystyle \sqrt{6}\)
- \(\displaystyle -\sqrt{15}\)
- \(\displaystyle 2\sqrt{m}\)
18.
- \(\displaystyle (\sqrt{2b})(\sqrt{2b})\)
- \(\displaystyle (3\sqrt{a})(3\sqrt{a})\)
- \(\displaystyle (2\sqrt[3]{b})^3\)
Exercise Group.
For Problems 19–20, put each set of numbers in order from smallest to largest.Try not to use a calculator.
19.
\(\dfrac{5}{4},~ 2, ~\sqrt{8},~ 2.3\)Answer.
\(\dfrac{5}{4},~ 2,~ 2.3,~ \sqrt{8}\)
20.
\(2\sqrt{3},~ 3,~ \dfrac{23}{6},~ \sqrt{6}\)Exercise Group.
For Problems 21–23, evaluate the expression for the given values of \(x\text{.}\) Round your answers to three decimal places if necessary.
21.
\(\sqrt{x^2-4}~~~~~~~~x=3, \sqrt{5}, -2\)Answer.
\(\sqrt{5} \approx 2.236,~1,~0\)
22.
\(\sqrt{x}-\sqrt{x-3}~~~~~~~~x=1, 4, 100\)23.
\(2x^2-4x~~~~~~~~x=-3, \sqrt{2}, \dfrac{1}{4}\)Answer.
\(30,~4-4\sqrt{2} \approx -1.657,~\dfrac{-7}{8}\)
24.
The distance \(m\) in miles that you can see on a clear day from a height of \(h\) miles is given by the formula
\begin{equation*}
m=89.4\sqrt{h}
\end{equation*}
How far can you see from an airplane flying at an altitude of 4.7 miles?
25.
The period of a pendulum (the time it takes to complete one full swing) is given in seconds by the formula
\begin{equation*}
T=6.28\sqrt{\dfrac{L}{32}}
\end{equation*}
where \(L\) is the length of the pendulum in feet. What is the period of the Foucault pendulum in the United Nations Headquarters in New York, whose length is 75 feet?
Answer.
9.61 seconds
26.
What is a rational number? An irrational number? Give examples of each.
27.
Give three examples of square roots that represent rational numbers, and three that are irrational.
Answer.
\(\sqrt{4},~\sqrt{9},~\sqrt{64};~\sqrt{2},~\sqrt{6},~\sqrt{11}\)
28.
Identify each number as rational or irrational.
- \(\displaystyle \sqrt{6}\)
- \(\displaystyle \dfrac{-5}{3}\)
- \(\displaystyle \sqrt{16}\)
- \(\displaystyle \sqrt{\dfrac{5}{9}}\)
- \(\displaystyle 6.008\)
- \(\displaystyle 3.\overline{23}\)
Exercise Group.
For Problems 29–32, decide whether the two expressions are equivalent by completing the table.
29.
Does \(~(a+b)^2=a^2+b^2~\text{?}\)
| \(a\) | \(b\) | \(a+b\) | \((a+b)^2\) | \(a^2\) | \(b^2\) | \(a^2+b^2\) |
| \(2\) | \(3\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(3\) | \(4\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(1\) | \(5\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(-2\) | \(6\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
Answer.
No
30.
Does \(~\sqrt{a^2+b^2}=a+b~\text{?}\)
| \(a\) | \(b\) | \(a+b\) | \(a^2\) | \(b^2\) | \(a^2+b^2\) | \(\sqrt{a^2+b^2}\) |
| \(3\) | \(4\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(2\) | \(5\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(1\) | \(6\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(-2\) | \(-3\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
31.
Does \(~\sqrt{a+b}=\sqrt{a}+\sqrt{b}~\text{?}\)
| \(a\) | \(b\) | \(a+b\) | \(\sqrt{a+b}\) | \(\sqrt{a}\) | \(\sqrt{b}\) | \(\sqrt{a}+\sqrt{b}\) |
| \(2\) | \(7\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(4\) | \(9\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(1\) | \(5\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(9\) | \(16\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
Answer.
No
32.
Does \((\sqrt{a}+\sqrt{b})^2=a+b~\text{?}\)
| \(a\) | \(b\) | \(a+b\) | \(\sqrt{a}\) | \(\sqrt{b}\) | \(\sqrt{a}+\sqrt{b}\) | \((\sqrt{a}+\sqrt{b})^2\) |
| \(4\) | \(9\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(1\) | \(4\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(3\) | \(5\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
| \(6\) | \(10\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) | \(\hphantom{0000}\) |
